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4x^2-27x-35=0
a = 4; b = -27; c = -35;
Δ = b2-4ac
Δ = -272-4·4·(-35)
Δ = 1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{1289}}{2*4}=\frac{27-\sqrt{1289}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{1289}}{2*4}=\frac{27+\sqrt{1289}}{8} $
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